A particle moves on circular path of radius 5m with constant speed 5 m/s. The magnitude of its average acceleration when it completes half revolution is :-

The average acceleration of an object moving in a circular path is given by the formula:

a_avg = Δv / Δt

However, in this case, the speed of the particle is constant, which means there is no change in speed (Δv = 0). Therefore, the average acceleration of the particle is 0 m/s².

But if you are referring to the average angular acceleration, that's a different scenario. Angular acceleration is the rate of change of angular velocity. In a half revolution of a circle, the change in velocity direction is pi radians (180 degrees), but the magnitude of the velocity remains the same.

So, even though the speed is constant, the velocity (which is a vector quantity that considers direction) is changing due to the change in direction.

In this case, the average angular acceleration would be calculated considering the change in velocity direction. But since the speed is constant, the magnitude of the average acceleration is still 0 m/s².