What is the minimum resistance which can be made using fiveresistors each of 1/5 Ω

The minimum resistance that can be made using five resistors each of 1/5 Ω can be achieved by connecting all the resistors in parallel.

Here's the step by step process:

1. Understand the concept: When resistors are connected in parallel, the total resistance decreases. This is because the electric current has more than one path to follow.

2. Use the formula for resistors in parallel: 1/Rt = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn. In this case, each resistor (R1, R2, R3, etc.) has a resistance of 1/5 Ω.

3. Substitute the values into the formula: 1/Rt = 1/(1/5) + 1/(1/5) + 1/(1/5) + 1/(1/5) + 1/(1/5) = 5 + 5 + 5 + 5 + 5 = 25.

4. Solve for Rt: 1/Rt = 25, so Rt = 1/25 Ω.

So, the minimum resistance that can be made using five resistors each of 1/5 Ω, when connected in parallel, is 1/25 Ω.