How many 16 ΩΩ resistors must be connected in series to give an equivalent resistance to five 800 ΩΩ resistors connected in parallel?
Question
How many 16 ΩΩ resistors must be connected in series to give an equivalent resistance to five 800 ΩΩ resistors connected in parallel?
Solution
Step 1: Find the equivalent resistance of five 800 Ω resistors connected in parallel.
The formula for total resistance (Rt) of resistors in parallel is given by 1/Rt = 1/R1 + 1/R2 + ... + 1/Rn.
In this case, all resistors have the same resistance (R = 800 Ω), so the formula simplifies to 1/Rt = n/R, where n is the number of resistors.
So, 1/Rt = 5/800.
Solving for Rt gives Rt = 800/5 = 160 Ω.
Step 2: Find the number of 16 Ω resistors needed to give the same resistance.
When resistors are connected in series, the total resistance is simply the sum of the individual resistances.
So, if each resistor has a resistance of 16 Ω, the number of resistors needed is Rt/16 = 160/16 = 10.
Therefore, 10 resistors of 16 Ω each are needed to give the same resistance as five 800 Ω resistors connected in parallel.
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