There are five resistances of 1 ohm each. If the initial three resistance are joined in parallel and rest two are joined in series, then the final resistance is
Question
There are five resistances of 1 ohm each. If the initial three resistance are joined in parallel and rest two are joined in series, then the final resistance is
Solution
First, let's calculate the total resistance for the three resistors connected in parallel. The formula for total resistance (Rt) in a parallel circuit is 1/Rt = 1/R1 + 1/R2 + 1/R3.
Given that R1 = R2 = R3 = 1 ohm, we can substitute these values into the formula:
1/Rt = 1/1 + 1/1 + 1/1 = 3
Therefore, Rt = 1/3 ohms for the parallel circuit.
Next, let's calculate the total resistance for the two resistors connected in series. The formula for total resistance in a series circuit is simply the sum of the individual resistances: Rt = R1 + R2.
Given that R1 = R2 = 1 ohm, we can substitute these values into the formula:
Rt = 1 + 1 = 2 ohms for the series circuit.
Finally, the total resistance of the circuit is the sum of the resistance of the parallel and series circuits:
Rt = 1/3 + 2 = 2 1/3 ohms or approximately 2.33 ohms.
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