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Which of the following function headers is correct?def try(a = 2, b = 3, c)def try(a = 2, b, c = 3)def try(a, b = 2, c = 3)def try(a, b, c = 3, d)

Question

Which of the following function headers is correct?def try(a = 2, b = 3, c)def try(a = 2, b, c = 3)def try(a, b = 2, c = 3)def try(a, b, c = 3, d)

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Solution

To determine which of the following function headers is correct, we need to consider the rules for defining function parameters.

  1. def try(a = 2, b = 3, c) This function header is incorrect because it has a parameter (c) without a default value. All parameters with default values should come after parameters without default values.

  2. def try(a = 2, b, c = 3) This function header is also incorrect because it has a parameter (b) without a default value. All parameters with default values should come after parameters without default values.

  3. def try(a, b = 2, c = 3) This function header is correct. It has three parameters (a, b, c), with the first parameter (a) having no default value, and the remaining parameters (b, c) having default values.

  4. def try(a, b, c = 3, d) This function header is incorrect because it has a parameter (d) without a default value. All parameters with default values should come after parameters without default values.

Therefore, the correct function header is: def try(a, b = 2, c = 3)

This problem has been solved

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