Which of the following function headers is correct?def try(a = 2, b = 3, c)def try(a = 2, b, c = 3)def try(a, b = 2, c = 3)def try(a, b, c = 3, d)
Question
Which of the following function headers is correct?def try(a = 2, b = 3, c)def try(a = 2, b, c = 3)def try(a, b = 2, c = 3)def try(a, b, c = 3, d)
Solution
To determine which of the following function headers is correct, we need to consider the rules for defining function parameters.
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def try(a = 2, b = 3, c) This function header is incorrect because it has a parameter (c) without a default value. All parameters with default values should come after parameters without default values.
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def try(a = 2, b, c = 3) This function header is also incorrect because it has a parameter (b) without a default value. All parameters with default values should come after parameters without default values.
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def try(a, b = 2, c = 3) This function header is correct. It has three parameters (a, b, c), with the first parameter (a) having no default value, and the remaining parameters (b, c) having default values.
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def try(a, b, c = 3, d) This function header is incorrect because it has a parameter (d) without a default value. All parameters with default values should come after parameters without default values.
Therefore, the correct function header is: def try(a, b = 2, c = 3)
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