Which of the following function headers is correct?def fun(a = 2, b = 3, c)def fun(a = 2, b, c = 3)def fun(a, b = 2, c = 3)def fun(a, b, c = 3, d)
Question
Which of the following function headers is correct?def fun(a = 2, b = 3, c)def fun(a = 2, b, c = 3)def fun(a, b = 2, c = 3)def fun(a, b, c = 3, d)
Solution
The correct function header is def fun(a, b = 2, c = 3)
In Python, non-default arguments (without a default value) should always precede default arguments (with a default value). The function headers def fun(a = 2, b = 3, c) and def fun(a = 2, b, c = 3) are incorrect because they have a non-default argument (c and b respectively) after a default argument.
The function header def fun(a, b, c = 3, d) is incorrect because it has a non-default argument (d) after a default argument (c = 3).
The function header def fun(a, b = 2, c = 3) is correct because all non-default arguments (a) precede default arguments (b = 2, c = 3).
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