Knowee
Questions
Features
Study Tools

Find the product of (4x2 – 9) and (2x2 – 3x + 1) and divide the product by (4x2 – 7x + 3). Then the quotient will be _______. Is (4x2 – 7x + 3) a factor of the product?A 2x2 + 1, No B 2x, No C 2x – 3, Yes D 2x – 1, Yes

Question

Find the product of (4x2 – 9) and (2x2 – 3x + 1) and divide the product by (4x2 – 7x + 3). Then the quotient will be _______. Is (4x2 – 7x + 3) a factor of the product?A 2x2 + 1, No B 2x, No C 2x – 3, Yes D 2x – 1, Yes

🧐 Not the exact question you are looking for?Go ask a question

Solution

To solve this problem, we first need to multiply the two polynomials (4x^2 – 9) and (2x^2 – 3x + 1).

Multiplying these two polynomials, we get:

8x^4 - 12x^3 + 4x^2 - 18x^2 + 27x - 9

Simplifying this, we get:

8x^4 - 12x^3 - 14x^2 + 27x - 9

Next, we divide this product by the polynomial (4x^2 – 7x + 3).

However, without doing the division, we can't definitively say whether (4x^2 – 7x + 3) is a factor of the product. A polynomial is a factor of another if, when divided, there is no remainder.

So, without further information or calculations, we can't answer the question. The options provided (A, B, C, D) don't seem to correspond to the steps we've taken so far.

This problem has been solved

Similar Questions

A factor of 2x³-7x²-5x+4 is

Factor completely 81x4 − 16. (3x − 2)(3x − 2)(9x2 + 4) (3x − 2)(3x + 2)(9x2 − 4) (3x − 2)(3x + 2)(9x2 + 4) (3x + 2)(3x + 2)(9x2 + 4)

What is the factorization of the expression below?16x2 - 49A.(4x - 7)(4x - 7)B.(8x + 7)(2x - 7)C.(8x - 7)(2x - 7)D.(4x + 7)(4x - 7)SUBMITarrow_backPREVIOUS

Factor completely x3 + 7x2 − 9x − 63. (x2 + 9)(x + 7) (x2 − 9)(x + 7) (x + 3)(x − 3)(x + 7) (x + 3)(x − 3)(x − 7)

What are the factors of 3x2 + 23x − 8? (3x − 4)(x + 2) (3x − 2)(x + 4) (3x − 8)(x + 1) (3x − 1)(x + 8)

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.