What will be the output of the following pseudo code?1. Integer p, q, r2. Set p=7, q=6, r=83. if((p^9^8) > (p^5))4. p = (12+4) +r5. End if6. Print p+q+r
Question
What will be the output of the following pseudo code?1. Integer p, q, r2. Set p=7, q=6, r=83. if((p^9^8) > (p^5))4. p = (12+4) +r5. End if6. Print p+q+r
Solution
The output of the pseudo code will be calculated as follows:
- The variables p, q, and r are set to 7, 6, and 8 respectively.
- The if condition checks if (p^9^8) is greater than (p^5). Here, "^" is usually used to denote exponentiation. However, in some programming languages, it is used to denote bitwise XOR operation. Without knowing the exact context, it's hard to determine the exact operation. But let's assume it's exponentiation for this case.
- (p^9^8) would be a very large number and (p^5) would be 16807. So, the condition is true.
- Since the condition is true, p is set to (12+4) + r, which is 24.
- Finally, p+q+r is printed, which is 24+6+8 = 38.
So, the output of the pseudo code will be 38.
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