Knowee
Questions
Features
Study Tools

You make 500 mL of a solution of cobalt(II) nitrate with concentration 0.250 mol L−1. You dilute this solution to 800 mL. Which of the following statements about your diluted solution is correct?

Question

You make 500 mL of a solution of cobalt(II) nitrate with concentration 0.250 mol L−1. You dilute this solution to 800 mL. Which of the following statements about your diluted solution is correct?

🧐 Not the exact question you are looking for?Go ask a question

Solution

To answer this question, we first need to calculate the number of moles of cobalt(II) nitrate in the original solution.

Step 1: Calculate the number of moles in the original solution The number of moles (n) can be calculated using the formula n = C*V, where C is the concentration and V is the volume.

In this case, C = 0.250 mol/L and V = 0.500 L (since 500 mL = 0.500 L), so n = 0.250 mol/L * 0.500 L = 0.125 mol.

Step 2: Calculate the concentration of the diluted solution The number of moles of cobalt(II) nitrate will remain the same after dilution, but the volume of the solution will increase.

The new volume is 800 mL = 0.800 L.

We can calculate the new concentration (C') using the formula C' = n/V'.

In this case, n = 0.125 mol and V' = 0.800 L, so C' = 0.125 mol / 0.800 L = 0.156 mol/L.

So, the correct statement about the diluted solution is that its concentration of cobalt(II) nitrate is 0.156 mol/L.

This problem has been solved

Similar Questions

Dilution: when 100. ml of a 2.50 M solution is diluted to 200. mL, what is the Molarity of the diluted solution?Group of answer choices5.00 M0.500 M1.25 M0.250 M

Determine which of these actions will dilute a solution.Add more soluteRemove soluteAdd more solventRemove solventI'm not sure

A 2600 mL solution of Mn(ClO4)2 is diluted from its original concentration of 1.66 M to a new concentration of 0.32 M. What is the resulting volume of the diluted solution?

A solution of Cs2SO4 at 2.0 M is diluted from its original volume of 0.6 L by adding 0.4 L. What is the resulting concentration of this solution?

You need 250.0 mL of a 0.0774 M solution of sodium nitrate to use in the laboratory. What volume of a 0.278 M stock solution would you need to dilute to achieve this concentration?Question 8Answer25.0 mL69.6 mL5.4 mL11618.6 mL10.0 mL

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.