A 2600 mL solution of Mn(ClO4)2 is diluted from its original concentration of 1.66 M to a new concentration of 0.32 M. What is the resulting volume of the diluted solution?
Question
A 2600 mL solution of Mn(ClO4)2 is diluted from its original concentration of 1.66 M to a new concentration of 0.32 M. What is the resulting volume of the diluted solution?
Solution
To solve this problem, we can use the formula M1V1 = M2V2, where M1 and V1 are the initial molarity and volume, and M2 and V2 are the final molarity and volume.
Given: M1 = 1.66 M (initial molarity) V1 = 2600 mL (initial volume) M2 = 0.32 M (final molarity)
We need to find V2 (final volume).
Substituting the given values into the formula, we get:
1.66 M * 2600 mL = 0.32 M * V2
Solving for V2, we get:
V2 = (1.66 M * 2600 mL) / 0.32 M
V2 = 8450 mL
So, the resulting volume of the diluted solution is 8450 mL.
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