Knowee
Questions
Features
Study Tools

90 g of Cr(ClO4)2 is dissolved in water to produce a solution with a concentration of 0.154 M. What is the volume of this solution in liters?

Question

90 g of Cr(ClO4)2 is dissolved in water to produce a solution with a concentration of 0.154 M. What is the volume of this solution in liters?

🧐 Not the exact question you are looking for?Go ask a question

Solution

Sure, here's how you can solve this problem:

Step 1: Determine the molar mass of Cr(ClO4)2. The molar mass of Cr is approximately 52 g/mol, Cl is approximately 35.5 g/mol, and O is approximately 16 g/mol. Since there are 2 Cl and 8 O atoms in Cr(ClO4)2, the molar mass is 52 + 2*(35.5 + 416) = 52 + 299 = 250 g/mol.

Step 2: Convert the mass of Cr(ClO4)2 to moles using the molar mass. 90 g / 250 g/mol = 0.36 moles.

Step 3: Use the definition of molarity (moles of solute / volume of solution in liters) to find the volume. 0.154 M = 0.36 moles / volume. Solving for volume gives volume = 0.36 moles / 0.154 M = 2.34 liters.

So, the volume of the solution is approximately 2.34 liters.

This problem has been solved

Similar Questions

0.209 mol of Cr₂(SO₄)₃ is dissolved in water to produce a solution with a concentration of 2.28 M. What is the volume of this solution in liters?

96 g of B2O3 is dissolved in water to produce a solution with a concentration of 1.86 M. What is the volume of this solution in liters?

0.13 mol of TiCl4 is dissolved in water to produce a solution with a concentration of 2 M. What is the volume of this solution in liters?

A 2600 mL solution of Mn(ClO4)2 is diluted from its original concentration of 1.66 M to a new concentration of 0.32 M. What is the resulting volume of the diluted solution?

16.2 g of MgS are dissolved in water.  If the volume of the solution is 250.0 mL, what is the concentration of the solution?  Report your answer in units of molarity.

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.