What will be the value of “sum” after the following code snippet terminates?void solve(ListNode* root) { /* The LinkedList is defined as: root-> val = value of the node root-> next = address of next element from the node The List is 1 -> 2 -> 3 -> 4 -> 5 */ int sum = 0; while (root != NULL) { sum += root -> val; root = root -> next; } printf("%d",sum);}*2 points152051
Question
What will be the value of “sum” after the following code snippet terminates?void solve(ListNode* root) { /* The LinkedList is defined as: root-> val = value of the node root-> next = address of next element from the node The List is 1 -> 2 -> 3 -> 4 -> 5 */ int sum = 0; while (root != NULL) { sum += root -> val; root = root -> next; } printf("%d",sum);}*2 points152051
Solution
The value of "sum" after the code snippet terminates will be 15.
Here is a step-by-step explanation of how the value is calculated:
- Initialize the variable "sum" to 0.
- Enter the while loop.
- Check if the current node, "root", is not NULL.
- If the condition is true, add the value of the current node, "root->val", to the "sum".
- Update the "root" to point to the next node, "root->next".
- Repeat steps 3-5 until the current node, "root", becomes NULL.
- Exit the while loop.
- Print the value of "sum" using the printf function.
In this case, the while loop iterates through each node of the linked list and adds the value of each node to the "sum" variable. The final value of "sum" is 15, which is the sum of all the values in the linked list (1 + 2 + 3 + 4 + 5).
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