What will be the output of the following code snippet for the list 1->2->3->4->5->6?void solve(struct node* start){if(start == NULL)return;printf("%d ", start->data);if(start->next != NULL )solve(start->next->next);printf("%d ", start->data);}*2 points1 2 3 4 5 61 3 5 5 3 61 3 5 1 3 52 4 6 1 3 5

The given code snippet is written in C programming language.

The code defines a function called "solve" that takes a pointer to a structure called "node" as a parameter.

The function first checks if the start pointer is NULL. If it is, the function returns and does nothing.

If the start pointer is not NULL, the function prints the value of the "data" member of the start node using the printf function.

Next, the function checks if the "next" pointer of the start node is not NULL. If it is not NULL, the function calls itself recursively with the "next" pointer of the "next" node.

After the recursive call, the function prints the value of the "data" member of the start node again.

To determine the output of the code snippet for the given list 1->2->3->4->5->6, we need to trace the execution of the code.

Initially, the solve function is called with the start pointer pointing to the first node of the list, which is 1.

The function prints the value of the "data" member of the start node, which is 1.

Then, it checks if the "next" pointer of the start node is not NULL. Since it is not NULL, the function calls itself recursively with the "next" pointer of the "next" node, which is 3.

In the recursive call, the function prints the value of the "data" member of the start node, which is 3.

Again, it checks if the "next" pointer of the start node is not NULL. Since it is not NULL, the function calls itself recursively with the "next" pointer of the "next" node, which is 5.

In the second recursive call, the function prints the value of the "data" member of the start node, which is 5.

Now, the function checks if the "next" pointer of the start node is not NULL. Since it is NULL, the recursive call ends and the function returns to the previous recursive call.

In the previous recursive call, the function prints the value of the "data" member of the start node again, which is 3.

Finally, the function returns to the initial call and prints the value of the "data" member of the start node again, which is 1.

Therefore, the output of the code snippet for the list 1->2->3->4->5->6 will be: 1 3 5 3 1.