Knowee
Questions
Features
Study Tools

The following C function takes a single-linked list of integers as a parameter and rearranges the elements of the list. The function is called with the list containing the integers 1, 2, 3, 4, 5, 6, 7 in the given order. What will be the contents of the list after the function completes execution?struct node{  int value;  struct node *next;};void rearrange(struct node *list){  struct node *p, * q;  int temp;  if ((!list) || !list->next)      return;  p = list;  q = list->next;  while(q)  {     temp = p->value;     p->value = q->value;     q->value = temp;     p = q->next;     q = p?p->next:0;  }}1,2,3,4,5,6,72,1,4,3,6,5,72,3,4,5,6,7,11,3,2,5,4,7,6

Question

The following C function takes a single-linked list of integers as a parameter and rearranges the elements of the list. The function is called with the list containing the integers 1, 2, 3, 4, 5, 6, 7 in the given order. What will be the contents of the list after the function completes execution?struct node{  int value;  struct node *next;};void rearrange(struct node *list){  struct node *p, * q;  int temp;  if ((!list) || !list->next)      return;  p = list;  q = list->next;  while(q)  {     temp = p->value;     p->value = q->value;     q->value = temp;     p = q->next;     q = p?p->next:0;  }}1,2,3,4,5,6,72,1,4,3,6,5,72,3,4,5,6,7,11,3,2,5,4,7,6

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

The correct answer is 2,1,4,3,6,5,7.

Here's the step-by-step explanation:

  1. The function rearrange takes a linked list as input. If the list is empty or has only one node, the function returns without making any changes.

  2. Two pointers p and q are initialized to point to the first and second nodes of the list respectively.

  3. The function enters a loop that continues until q (the second pointer) is NULL. Inside the loop, the values of the nodes pointed to by p and q are swapped.

  4. The pointers p and q are then moved two steps forward. If p is not NULL, q is set to the next node; otherwise, q is set to NULL.

  5. The loop continues until q becomes NULL, which means all pairs of nodes have been processed.

  6. After the function completes, the list will have the pairs of nodes swapped. So, the list 1,2,3,4,5,6,7 becomes 2,1,4,3,6,5,7.

This problem has been solved

Similar Questions

What is the output of the following function for a single linked list with the values1 -> 2 -> 3 -> 4 -> 5-> 6? start is pointing to the first node in the list.void fun(struct node *start){if (start == NULL) return;printf(“%d”, start->data);if (start-> next != NULL){fun (start-> next -> next);printf(“%d”, start->data);}}

What will be the output of the following code snippet for the list 1->2->3->4->5->6?void solve(struct node* start){if(start == NULL)return;printf("%d ", start->data);if(start->next != NULL )solve(start->next->next);printf("%d ", start->data);}*2 points1 2 3 4 5 61 3 5 5 3 61 3 5 1 3 52 4 6 1 3 5

Write a C program to reverse a single linked list recursively. #include <stdio.h> #include <stdlib.h> struct Node { int data; struct Node* next; }; // Write a function to create a new node with the given data // Write a function to print the linked list // Write a function to reverse the linked list recursively // Write your main function here

he following function reverse() is supposed to reverse a singly linked list. There is one line missing at the end of the function./* Link list node */struct node{    int data;    struct node* next;};  /* head_ref is a double pointer which points to head (or start) pointer   of linked list */static void reverse(struct node** head_ref){    struct node* prev   = NULL;    struct node* current = *head_ref;    struct node* next;    while (current != NULL)    {        next  = current->next;          current->next = prev;           prev = current;        current = next;    }    /*ADD A STATEMENT HERE*/}  What should be added in place of “/*ADD A STATEMENT HERE*/”, so that the function correctly reverses a linked list.

Write a function that searches a linked list for the integers that occur more than once, and removes all their occurrences except for the first occurrences. The function does not remove the integers that occur only once. Removed nodes must be freed. Each node is defined asstruct node{     int data;     struct node * next;};The function is declared as follows. Its input is the head pointer of the linked list. It returns the head pointer of the linked list after the removal.struct node *remove_repeated_integer(struct node *list);

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.