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Type the program's outputa = int(input())b = int(input())c = int(input())while a < b: print(a) if a > c: break a += 3 Input32412Output

Question

Type the program's outputa = int(input())b = int(input())c = int(input())while a < b: print(a) if a > c: break a += 3 Input32412Output

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Solution

The program first takes three inputs from the user and assigns them to variables a, b, and c. Then, it enters a while loop that continues as long as the value of 'a' is less than 'b'. Inside the loop, it prints the current value of 'a'. Then, it checks if 'a' is greater than 'c'. If it is, it breaks the loop. If not, it increments 'a' by 3.

Given the input values of 3, 24, and 12, the output would be:

3 6 9

This is because the loop starts with 'a' equal to 3, which is less than 'b' (24), so it enters the loop. It prints 'a' (3), then checks if 'a' is greater than 'c' (12). It's not, so it increments 'a' by 3 to 6.

On the next iteration, 'a' is still less than 'b', so it prints 'a' (6), checks if 'a' is greater than 'c' (it's not), and increments 'a' by 3 to 9.

On the third iteration, the same process happens again, printing 9.

On the fourth iteration, 'a' is now 12, which is equal to 'c'. Since 'a' is not greater than 'c', it increments 'a' by 3 to 15. Now, 'a' is greater than 'c', so it breaks the loop and the program ends.

So, the output is:

3 6 9

This problem has been solved

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