What will be the output of the following Python program? i = 0while i < 5: print(i) i += 1 if i == 3: breakelse: print(0)error0 1 2 00 1 2none of the mentioned
Question
What will be the output of the following Python program? i = 0while i < 5: print(i) i += 1 if i == 3: breakelse: print(0)error0 1 2 00 1 2none of the mentioned
Solution
The output of the given Python program will be:
0 1 2
Here's the step-by-step explanation:
- The program starts with
i = 0. - It enters the while loop because
i < 5is true. - It prints the current value of
i, which is 0. - It increments
iby 1, soiis now 1. - It checks if
i == 3. It's not, so it doesn't break and goes back to the start of the loop. - It prints the current value of
i, which is 1. - It increments
iby 1, soiis now 2. - It checks if
i == 3. It's not, so it doesn't break and goes back to the start of the loop. - It prints the current value of
i, which is 2. - It increments
iby 1, soiis now 3. - It checks if
i == 3. It is, so it breaks the loop and the program ends. Theelseclause associated with thewhileloop does not execute because the loop was exited via abreakstatement.
So, the correct answer is "0 1 2".
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