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What will be the output of the following Python program?  i = 0while i < 5: print(i) i += 1 if i == 3: breakelse: print(0)error0 1 2 00 1 2none of the mentioned

Question

What will be the output of the following Python program?  i = 0while i < 5: print(i) i += 1 if i == 3: breakelse: print(0)error0 1 2 00 1 2none of the mentioned

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Solution

The output of the given Python program will be:

0 1 2

Here's the step-by-step explanation:

  1. The program starts with i = 0.
  2. It enters the while loop because i < 5 is true.
  3. It prints the current value of i, which is 0.
  4. It increments i by 1, so i is now 1.
  5. It checks if i == 3. It's not, so it doesn't break and goes back to the start of the loop.
  6. It prints the current value of i, which is 1.
  7. It increments i by 1, so i is now 2.
  8. It checks if i == 3. It's not, so it doesn't break and goes back to the start of the loop.
  9. It prints the current value of i, which is 2.
  10. It increments i by 1, so i is now 3.
  11. It checks if i == 3. It is, so it breaks the loop and the program ends. The else clause associated with the while loop does not execute because the loop was exited via a break statement.

So, the correct answer is "0 1 2".

This problem has been solved

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