The latent heats for some substances are given below.Substance Latent Heat of FusionJ/kg Latent Heat of VaporizationJ/kgLead 0.25 E5 8.68 E5Mercury 0.12 E5 2.7 E5How much heat is needed to melt 15.0 kg of lead at its melting point? 1.80 E5 J 3.75 E5 J 4.05 E6 J 1.30 E7 J
Question
The latent heats for some substances are given below.Substance Latent Heat of FusionJ/kg Latent Heat of VaporizationJ/kgLead 0.25 E5 8.68 E5Mercury 0.12 E5 2.7 E5How much heat is needed to melt 15.0 kg of lead at its melting point? 1.80 E5 J 3.75 E5 J 4.05 E6 J 1.30 E7 J
Solution
The amount of heat needed to melt a substance can be calculated using the formula:
Q = m * L_f
where: Q = heat energy required (in Joules) m = mass of the substance (in kg) L_f = latent heat of fusion of the substance (in J/kg)
Given in the problem: m = 15.0 kg (mass of lead) L_f = 0.25 E5 J/kg (latent heat of fusion for lead)
Substituting these values into the formula:
Q = 15.0 kg * 0.25 E5 J/kg
Q = 3.75 E5 J
So, the heat needed to melt 15.0 kg of lead at its melting point is 3.75 E5 J.
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