When 3.64×10 5 J of energy is absorbed by 2.0kg of a pure solid at its melting point, exactly half of it melts. What is the latent heat of fusion of this solid?
Question
When 3.64×10 5 J of energy is absorbed by 2.0kg of a pure solid at its melting point, exactly half of it melts. What is the latent heat of fusion of this solid?
Solution
Step 1: Identify the given values. The energy absorbed (Q) = 3.64×10^5 J The mass of the solid (m) = 2.0 kg Only half of the solid melts, so the mass of the melted solid (m') = m/2 = 1.0 kg
Step 2: Use the formula for latent heat. The formula for latent heat (L) is L = Q/m', where Q is the heat absorbed and m' is the mass of the substance that changes phase.
Step 3: Substitute the given values into the formula. L = Q/m' = 3.64×10^5 J / 1.0 kg = 3.64×10^5 J/kg
So, the latent heat of fusion of the solid is 3.64×10^5 J/kg.
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