This is a chemical equation representing the ionization of acetic acid (CH3COOH) in water (H2O). Here's a step-by-step breakdown:

1. Acetic acid (CH3COOH) reacts with water (H2O). This is a reversible reaction, as indicated by the ' sign.

2. The acetic acid donates a proton (H+) to the water molecule. This is because acetic acid is a weak acid and can donate a proton.

3. The acetic acid molecule becomes a acetate ion (CH3COO-) after losing a proton.

4. The water molecule becomes a hydronium ion (H3O+) after gaining a proton.

So, the equation shows that when acetic acid is added to water, it ionizes to form acetate ions and hydronium ions.

Question

This is a chemical equation representing the ionization of acetic acid (CH3COOH) in water (H2O). Here's a step-by-step breakdown:

1. Acetic acid (CH3COOH) reacts with water (H2O). This is a reversible reaction, as indicated by the ' sign.

2. The acetic acid donates a proton (H+) to the water molecule. This is because acetic acid is a weak acid and can donate a proton.

3. The acetic acid molecule becomes a acetate ion (CH3COO-) after losing a proton.

4. The water molecule becomes a hydronium ion (H3O+) after gaining a proton.

So, the equation shows that when acetic acid is added to water, it ionizes to form acetate ions and hydronium ions.

Knowee AI · Accepted Answer

This is a chemical equation representing the ionization of acetic acid (CH3COOH) in water (H2O). Here's a step-by-step breakdown:

1. Acetic acid (CH3COOH) reacts with water (H2O). This is a reversible reaction, as indicated by the ' sign.

2. The acetic acid donates a proton (H+) to the water molecule. This is because acetic acid is a weak acid and can donate a proton.

3. The acetic acid molecule becomes a acetate ion (CH3COO-) after losing a proton.

4. The water molecule becomes a hydronium ion (H3O+) after gaining a proton.

So, the equation shows that when acetic acid is added to water, it ionizes to form acetate ions and hydronium ions.

CH3COOH + H2O ' CH3COO- + H3O+