A few kids decide to go to the park to go on the merry-go-round. They are the only ones there so the merry-go-round is not moving yet. They push it for 3.00 s and it moves over an angle of 93.0°. What is the final angular velocity of the merry-go-round? 3.92 rad/s 5.82 rad/s 1.08 rad/s 12.8 rad/s
Question
A few kids decide to go to the park to go on the merry-go-round. They are the only ones there so the merry-go-round is not moving yet. They push it for 3.00 s and it moves over an angle of 93.0°. What is the final angular velocity of the merry-go-round? 3.92 rad/s 5.82 rad/s 1.08 rad/s 12.8 rad/s
Solution
To solve this problem, we need to use the formula for angular velocity, which is the change in angle (in radians) divided by the change in time.
First, we need to convert the angle from degrees to radians. We know that 180 degrees is equal to π radians. So, 93.0 degrees is equal to (93.0/180)*π = 1.623 radians.
Next, we divide this by the time to find the angular velocity. So, the final angular velocity of the merry-go-round is 1.623 radians / 3.00 s = 0.541 rad/s.
However, this answer is not in the options provided. It seems like there might be a mistake in the problem or the answer choices.
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