A child is riding a merry-go-round which completes one revolution every 8.36 s.The child is standing 4.65 m from the center of the merry-go-round.What is the tangential speed of the child?Express your answer in m/s.

The tangential speed (v) of the child can be calculated using the formula for the circumference of a circle (C = 2πr) divided by the time it takes to complete one revolution (T).

Here's the step-by-step calculation:

1. Identify the given values:

   • The radius (r) of the circle, which is the distance from the center of the merry-go-round to the child, is 4.65 m.
   • The time for one revolution (T) is 8.36 s.

2. Calculate the circumference of the circle (C) using the formula C = 2πr:

   • C = 2 * π * 4.65 m = 29.22 m

3. Calculate the tangential speed (v) by dividing the circumference by the time for one revolution:

   • v = C / T = 29.22 m / 8.36 s = 3.49 m/s

So, the tangential speed of the child is approximately 3.49 m/s.

The tangential speed (v) of the child can be calculated using the formula for the circumference of a circle (2πr) divided by the time it takes to complete one revolution (T).

The formula is: v = 2πr/T

Given:

• r (radius) = 4.65 m
• T (time period) = 8.36 s

Substituting these values into the formula, we get:

v = 2π(4.65 m) / 8.36 s

Now, calculate the value:

v = 2 * 3.1416 * 4.65 m / 8.36 s = 1.75 m/s

So, the tangential speed of the child is approximately 1.75 m/s.

The tangential speed (v) of the child can be calculated using the formula for the circumference of a circle (2πr) divided by the time it takes to complete one revolution (T).

The formula is: v = 2πr/T

Given:

• r (radius) = 4.65 m
• T (time period) = 8.36 s

Substituting these values into the formula gives:

v = 2π(4.65 m) / 8.36 s

Now, calculate the value:

v = 2 * 3.1416 * 4.65 m / 8.36 s = 1.75 m/s

So, the tangential speed of the child is approximately 1.75 m/s.

The tangential speed (v) of the child can be calculated using the formula for the speed of an object moving in a circular path:

v = 2πr/T

where:

• r is the radius of the circle, which is the distance from the center of the merry-go-round to the child (4.65 m), and
• T is the period of the motion, which is the time it takes for one complete revolution (8.36 s).

Substituting the given values into the formula, we get:

v = 2π(4.65 m)/(8.36 s) ≈ 1.75 m/s

So, the tangential speed of the child is approximately 1.75 m/s.