A point on the rim of a 0.30-m-radius rotating wheel has a tangential speed of 4.0 m/s. What is the tangential speed of a point 0.20 m from the center of the same wheel?Select one:a.8.0 m/sb.1.3 m/sc.2.7 m/sd.1.0 m/s
Question
A point on the rim of a 0.30-m-radius rotating wheel has a tangential speed of 4.0 m/s. What is the tangential speed of a point 0.20 m from the center of the same wheel?Select one:a.8.0 m/sb.1.3 m/sc.2.7 m/sd.1.0 m/s
Solution
The tangential speed (v) of a point on a rotating wheel is given by the formula v = rω, where r is the radius of the wheel and ω is the angular velocity.
From the given problem, we know that a point on the rim of the wheel (r = 0.30 m) has a tangential speed of 4.0 m/s. We can use this information to find the angular velocity:
4.0 m/s = 0.30 m * ω => ω = 4.0 m/s / 0.30 m = 13.33 rad/s
Now, we can find the tangential speed of a point 0.20 m from the center of the wheel using the same formula:
v = rω = 0.20 m * 13.33 rad/s = 2.67 m/s
So, the tangential speed of a point 0.20 m from the center of the wheel is 2.67 m/s. Therefore, the correct answer is c. 2.7 m/s.
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