The centripetal acceleration (a) of a point in circular motion is given by the formula a = ω²r, where ω is the angular speed and r is the radius of the circle.

Given that a = 5.0 m/s² and r = 0.15 m, we can solve for ω using the formula:

ω = sqrt(a/r) = sqrt(5.0/0.15) = sqrt(33.33) = 5.77 rad/s

This is the angular speed of a point on the rim of the disk.

However, we are asked for the angular speed of a point 0.075 m from the center of the disk.

The angular speed ω is the same at all points on the disk, because all points on the disk make a full rotation in the same amount of time.

Therefore, the angular speed of a point 0.075 m from the center of the disk is also 5.77 rad/s.

So, the answer is c. 5.8 rad/s (rounded to one decimal place).

Question

The centripetal acceleration (a) of a point in circular motion is given by the formula a = ω²r, where ω is the angular speed and r is the radius of the circle.

Given that a = 5.0 m/s² and r = 0.15 m, we can solve for ω using the formula:

ω = sqrt(a/r) = sqrt(5.0/0.15) = sqrt(33.33) = 5.77 rad/s

This is the angular speed of a point on the rim of the disk.

However, we are asked for the angular speed of a point 0.075 m from the center of the disk.

The angular speed ω is the same at all points on the disk, because all points on the disk make a full rotation in the same amount of time.

Therefore, the angular speed of a point 0.075 m from the center of the disk is also 5.77 rad/s.

So, the answer is c. 5.8 rad/s (rounded to one decimal place).

Knowee AI · Accepted Answer

The centripetal acceleration (a) of a point in circular motion is given by the formula a = ω²r, where ω is the angular speed and r is the radius of the circle.

Given that a = 5.0 m/s² and r = 0.15 m, we can solve for ω using the formula:

ω = sqrt(a/r) = sqrt(5.0/0.15) = sqrt(33.33) = 5.77 rad/s

This is the angular speed of a point on the rim of the disk.

However, we are asked for the angular speed of a point 0.075 m from the center of the disk.

The angular speed ω is the same at all points on the disk, because all points on the disk make a full rotation in the same amount of time.

Therefore, the angular speed of a point 0.075 m from the center of the disk is also 5.77 rad/s.

So, the answer is c. 5.8 rad/s (rounded to one decimal place).

A point on the rim of a 0.15-m-radius rotating disk has a centripetal acceleration of 5.0 m/s2. What is the angular speed of a point 0.075 m from the center of the disk?Select one:a.0.89 rad/sb.3.2 rad/sc.5.8 rad/sd.1.6 rad/s

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