Merry Go Round (MGR) has a radius of 18 meters. At t = 0, the Merry Go Round (MGR) has an angular velocity of 1.2 radians/second. The MGR also has a constant angular acceleration. After 3 seconds have elapsed, MGR has an angular velocity of 2.5 radians/second. A RIDER IS STANDING AT THE OUTER EDGE OF THE MGR.(a) What is the angular acceleration of the MGR? radians/s^2
Question
Merry Go Round (MGR) has a radius of 18 meters. At t = 0, the Merry Go Round (MGR) has an angular velocity of 1.2 radians/second. The MGR also has a constant angular acceleration. After 3 seconds have elapsed, MGR has an angular velocity of 2.5 radians/second. A RIDER IS STANDING AT THE OUTER EDGE OF THE MGR.(a) What is the angular acceleration of the MGR? radians/s^2
Solution
The angular acceleration (α) can be calculated using the formula:
α = (ωf - ωi) / t
where: ωf = final angular velocity ωi = initial angular velocity t = time
Given in the problem: ωf = 2.5 rad/s ωi = 1.2 rad/s t = 3 s
Substituting these values into the formula, we get:
α = (2.5 rad/s - 1.2 rad/s) / 3 s = 1.3 rad/s^2
So, the angular acceleration of the MGR is 1.3 rad/s^2.
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