To solve this problem, we can use the equation of motion: v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement.

Given in the problem:
u = 20 m/s (initial velocity)
v = 0 m/s (final velocity, since the car comes to rest)
s = 50 m (displacement)

We need to find a (acceleration).

Substituting the given values into the equation:

0 = (20)^2 + 2*a*50

Solving for a, we get:

-400 = 100a

a = -400 / 100

a = -4 m/s^2

So, the correct answer is:

c. -4 m/s^2

The negative sign indicates that this is a deceleration, or slowing down, which makes sense because the car is coming to rest.

Question

To solve this problem, we can use the equation of motion: v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement.

Given in the problem:
u = 20 m/s (initial velocity)
v = 0 m/s (final velocity, since the car comes to rest)
s = 50 m (displacement)

We need to find a (acceleration).

Substituting the given values into the equation:

0 = (20)^2 + 2*a*50

Solving for a, we get:

-400 = 100a

a = -400 / 100

a = -4 m/s^2

So, the correct answer is:

c. -4 m/s^2

The negative sign indicates that this is a deceleration, or slowing down, which makes sense because the car is coming to rest.

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