A car moving initially at 20m/s, reduces its speed uniformlyand comes to rest through a displacement of 50m. Find the total time taken through the given displacement.a.4sb.5sc.10sd.3s
Question
A car moving initially at 20m/s, reduces its speed uniformlyand comes to rest through a displacement of 50m. Find the total time taken through the given displacement.a.4sb.5sc.10sd.3s
Solution
The total time taken can be found using the equation of motion:
v = u + at
where: v = final velocity u = initial velocity a = acceleration t = time
First, we need to find the acceleration using the equation:
v^2 = u^2 + 2as
Rearranging the equation to solve for a, we get:
a = (v^2 - u^2) / 2s
Plugging in the given values:
a = ((0 m/s)^2 - (20 m/s)^2) / (2*50 m) a = (-400 m²/s²) / 100 m a = -4 m/s²
Then, we can find the time using the first equation:
0 = 20 m/s - 4 m/s² * t
Rearranging the equation to solve for t, we get:
t = 20 m/s / 4 m/s² t = 5 s
Therefore, the total time taken through the given displacement is 5 seconds.
The correct answer is:
b. 5s
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