Sure, here is a simple shell script that will calculate the sum of all digits of a given number:

```bash
#!/bin/bash

# Read the number
echo "Enter a number: "
read num

# Initialize sum to 0
sum=0

# Calculate sum of digits
while [ $num -gt 0 ]
do
# Get last digit
digit=$((num % 10))

# Add digit to sum
sum=$((sum + digit))

# Remove last digit
num=$((num / 10))
done

# Print the sum
echo "The sum of all digits is: $sum"
```

Here's how this script works:

1. It first reads a number from the user.
2. It initializes a variable `sum` to 0. This variable will hold the sum of the digits.
3. It enters a while loop that continues as long as `num` is greater than 0.
4. Inside the loop, it calculates the last digit of `num` using the modulus operator `%` and stores it in `digit`.
5. It adds `digit` to `sum`.
6. It removes the last digit from `num` using integer division by 10.
7. Once the loop is done, it prints the sum of the digits.

Question

Sure, here is a simple shell script that will calculate the sum of all digits of a given number:

```bash
#!/bin/bash

# Read the number
echo "Enter a number: "
read num

# Initialize sum to 0
sum=0

# Calculate sum of digits
while [ $num -gt 0 ]
do
    # Get last digit
    digit=$((num % 10))

# Add digit to sum
    sum=$((sum + digit))

# Remove last digit
    num=$((num / 10))
done

# Print the sum
echo "The sum of all digits is: $sum"
```

Here's how this script works:

1. It first reads a number from the user.
2. It initializes a variable `sum` to 0. This variable will hold the sum of the digits.
3. It enters a while loop that continues as long as `num` is greater than 0.
4. Inside the loop, it calculates the last digit of `num` using the modulus operator `%` and stores it in `digit`.
5. It adds `digit` to `sum`.
6. It removes the last digit from `num` using integer division by 10.
7. Once the loop is done, it prints the sum of the digits.

Knowee AI · Accepted Answer

Sure, here is a simple shell script that will calculate the sum of all digits of a given number:

```bash
#!/bin/bash

# Read the number
echo "Enter a number: "
read num

# Initialize sum to 0
sum=0

# Calculate sum of digits
while [ $num -gt 0 ]
do
    # Get last digit
    digit=$((num % 10))

# Add digit to sum
    sum=$((sum + digit))

# Remove last digit
    num=$((num / 10))
done

# Print the sum
echo "The sum of all digits is: $sum"
```

Here's how this script works:

1. It first reads a number from the user.
2. It initializes a variable `sum` to 0. This variable will hold the sum of the digits.
3. It enters a while loop that continues as long as `num` is greater than 0.
4. Inside the loop, it calculates the last digit of `num` using the modulus operator `%` and stores it in `digit`.
5. It adds `digit` to `sum`.
6. It removes the last digit from `num` using integer division by 10.
7. Once the loop is done, it prints the sum of the digits.

Write a Shell script to print given numbers sum of all digits.

Question

Solution

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