Shown below are the marks scored by the students of two sections of a class. The strength of both sections is the same. Roll Number Section A Section BStudent 1 8.2 8.1Student 2 7.2 7.9Student 3 6.5 8.2Student 4 8.9 7.95Student 5 8.1 8.08Student 6 8 7.8Student 7 7.7 7.9Student 8 7.9 8.04Student 9 8.1 8.08Student 10 8.3 8.12Student 11 9 8.2Student 12 9 8Answer the following questions based on the table. Question 1/2MandatoryClass Performance: MeanCalculate the mean of marks scored by the students of each section.Section A: 8.075, Section B: 8.031Section A: 8.0, Section B: 8.3Section A: 7.3, Section B: 8.031Section A: 8.1, Section B: 8.031
Question
Shown below are the marks scored by the students of two sections of a class. The strength of both sections is the same. Roll Number Section A Section BStudent 1 8.2 8.1Student 2 7.2 7.9Student 3 6.5 8.2Student 4 8.9 7.95Student 5 8.1 8.08Student 6 8 7.8Student 7 7.7 7.9Student 8 7.9 8.04Student 9 8.1 8.08Student 10 8.3 8.12Student 11 9 8.2Student 12 9 8Answer the following questions based on the table. Question 1/2MandatoryClass Performance: MeanCalculate the mean of marks scored by the students of each section.Section A: 8.075, Section B: 8.031Section A: 8.0, Section B: 8.3Section A: 7.3, Section B: 8.031Section A: 8.1, Section B: 8.031
Solution
To calculate the mean of marks scored by the students of each section, we need to add up all the scores and then divide by the number of students.
For Section A: (8.2 + 7.2 + 6.5 + 8.9 + 8.1 + 8 + 7.7 + 7.9 + 8.1 + 8.3 + 9 + 9) / 12 = 8.075
For Section B: (8.1 + 7.9 + 8.2 + 7.95 + 8.08 + 7.8 + 7.9 + 8.04 + 8.08 + 8.12 + 8.2 + 8) / 12 = 8.031
So, the mean of marks scored by the students of Section A is 8.075 and for Section B is 8.031. Therefore, the correct answer is "Section A: 8.075, Section B: 8.031".
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