Let's shake on it: A random sample of 12-ounce milkshakes from 11 fast-food restaurants had the following number of calories.375 608 473 476 504 510 472700 642 591 580 Send data to ExcelAssume

(c) If appropriate, construct an 80% confidence interval for the mean calorie count for all 12-ounce milkshakes sold at fast-food restaurants. Round the answers to at least two decimal places.An 80% confidence interval for the mean calorie count for all 12-ounce milkshakes sold at fast-food restaurants is <<μ.

A survey of 10 fast-food restaurants noted the number of calories in a mid-sized hamburger. The results are given in the table below.Calories in a mid-sized hamburger513 506 501 499 496 506 459 478 463 514Find the mean and sample standard deviation of these data. Round to the nearest hundredth.mean sample standard deviation

Let's shake on it: A random sample of 12-ounce milkshakes from 11 fast-food restaurants had the following number of calories.375 608 473 476 504 510 472700 642 591 580 Send data to ExcelAssume the population standard deviation is =σ85.Part 1 of 3(a) Explain why it is necessary to check whether the population is approximately normal before constructing a confidence interval.It is necessary to check whether the population is approximately normal because ▼the sample size is less than or equal to 30.Part 2 of 3(b) Following is a dotplot of these data. Is it reasonable to assume that the population is approximately normal?350400450500550600650700It ▼is reasonable to assume that the population is approximately normal.Part: 2 / 32 of 3 Parts CompletePart 3 of 3(c) If appropriate, construct an 80% confidence interval for the mean calorie count for all 12-ounce milkshakes sold at fast-food restaurants. Round the answers to at least two decimal places.An 80% confidence interval for the mean calorie count for all 12-ounce milkshakes sold at fast-food restaurants is <<μ.

Eat your cereal: Boxes of cereal are labeled as containing 14 ounces. Following are the weights, in ounces, of a sample of 12 boxes. It is reasonable to assume that the population is approximately normal.13.09 14.53 13.18 13.19 13.17 13.0913.12 14.53 13.02 13.01 13.08 13.09Send data to ExcelPart: 0 / 20 of 2 Parts CompletePart 1 of 2Construct a 99% confidence interval for the mean weight. Round the answers to three decimal places. <<μ

A study was conducted in which students were asked to estimate the number of calories in a cheeseburger.One group was asked to do this after thinking about a calorie-laden cheesecake.A second group was asked to do this after thinking about an organic fruit salad.The mean number of calories estimated was 770 for the group that thought about the cheesecake and 1027 for the group that thought about the organic fruit salad.Suppose that the study was based on a sample of 20 students in each group,and the standard deviation of the number of calories estimated was 123 for the people who thought about the cheesecake first and 146 for the people who thought about the organic fruit salad first. At the 0.01 level of significance,is there evidence that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first? Find the test statistic. tsTAT=(Round to two decimal places as needed.)