Knowee
Questions
Features
Study Tools

A study was conducted in which students were asked to estimate the number of calories in a cheeseburger.One group was asked to do this after thinking about a calorie-laden cheesecake.A second group was asked to do this after thinking about an organic fruit salad.The mean number of calories estimated was 770 for the group that thought about the cheesecake and 1027 for the group that thought about the organic fruit salad.Suppose that the study was based on a sample of 20 students in each group,and the standard deviation of the number of calories estimated was 123 for the people who thought about the cheesecake first and 146 for the people who thought about the organic fruit salad first. At the 0.01 level of significance,is there evidence that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first? Find the test statistic. tsTAT=(Round to two decimal places as needed.)

Question

A study was conducted in which students were asked to estimate the number of calories in a cheeseburger.One group was asked to do this after thinking about a calorie-laden cheesecake.A second group was asked to do this after thinking about an organic fruit salad.The mean number of calories estimated was 770 for the group that thought about the cheesecake and 1027 for the group that thought about the organic fruit salad.Suppose that the study was based on a sample of 20 students in each group,and the standard deviation of the number of calories estimated was 123 for the people who thought about the cheesecake first and 146 for the people who thought about the organic fruit salad first. At the 0.01 level of significance,is there evidence that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first? Find the test statistic. tsTAT=(Round to two decimal places as needed.)

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

To find the test statistic, we will use the formula for the test statistic in a two-sample t-test:

t = (M1 - M2) / sqrt((SD1^2/n1) + (SD2^2/n2))

where: M1 and M2 are the sample means, SD1 and SD2 are the sample standard deviations, n1 and n2 are the sample sizes.

Here, M1 = 770, M2 = 1027, SD1 = 123, SD2 = 146, n1 = n2 = 20.

Substituting these values into the formula, we get:

t = (770 - 1027) / sqrt((123^2/20) + (146^2/20))

Now, calculate the values inside the square root:

= (770 - 1027) / sqrt((15129/20) + (21316/20))

= (770 - 1027) / sqrt(756.45 + 1065.8)

= (770 - 1027) / sqrt(1822.25)

= (770 - 1027) / 42.69

= -257 / 42.69

So, the test statistic t = -6.02 (rounded to two decimal places).

This problem has been solved

Similar Questions

State the conclusion of the test. Reject Ho.There is evidence that the mean number of estimated calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first. e.If you were developing a commercial for a cheeseburger,based on the results of(d),what other foods might you show in the commercial? OA.Show both the cheesecake and the organic fruit salad after showing the cheeseburger,so that the cheeseburger will appear healthier. O B.Show the cheesecake before showing the cheeseburger,so that the cheeseburger will appear healthier OC.Show the organic fruit salad before showing the cheeseburger,so that the cheeseburger will appear healthier. O D.Show both the cheesecake and the organic fruit salad before showing the cheeseburger,so that the cheeseburger will appear healthier.

For an upcoming government project, you are required to find the average height of the students in Class VIII of a given school. Instead of asking every student, you took a few students as your sample and noted their heights in the table given below. Roll Number Height8012 121.92 cm8045 133.21 cm8053 141.34 cm8099 126.23 cm8125 175.74 cmQuestion 3/3MandatorySamplingWhat is the standard deviation of the sample?22.8423.6719.1921.45

A random sample of 12 items is taken and is found to have a meanweight of 50 grams and a standard deviation of 9 gramsWhat is the mean weight of population1. with 95% confidence2. with 99% confidence

A manufacturer of chocolate candies uses machines to package candies as they move along a filling line.Although the packages are labeled as 8 ounces,the company wants the packages to contain a mean of 8.17 ounces so that virtually none of the packages contain less than 8 ounces.A sample of 50 packages is selected periodically,and the packaging process is stopped if there is evidence that the mean amount packaged is different from 8.17 ounces.Suppose that in a particular sample of 50 packages,the mean amount dispensed is 8.168 ounces,with a sample standard deviation of 0.059 ounce.Complete parts(a)and(b). Click here to view page 1 of the critical values for the t Distribution. Click here to view page 2 of the critical values for the t Distribution. 。○ State the null and alternative hypotheses H0μ=8.17 H1μ≠8.17 (Type integers or decimals.) Identify the critical value(s). The critical value(s)is(are)-2.6800,2.6800 (Round to four decimal places as needed.Use a comma to separate answers as needed.) Determine the test statistic.

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than 10 pounds. A consumer activist decides to test the authenticity of the claim. She follows the progress of 29 women who recently joined the weight-reduction program. She calculates the mean weight loss of these participants as 10.8 pounds with a standard deviation of 1.6 pounds. The test statistic for this hypothesis would be __________.Multiple Choice−3.023.02−2.69

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.