(c) If appropriate, construct an 80% confidence interval for the mean calorie count for all 12-ounce milkshakes sold at fast-food restaurants. Round the answers to at least two decimal places.An 80% confidence interval for the mean calorie count for all 12-ounce milkshakes sold at fast-food restaurants is <<μ.

Let's shake on it: A random sample of 12-ounce milkshakes from 11 fast-food restaurants had the following number of calories.375 608 473 476 504 510 472700 642 591 580 Send data to ExcelAssume

Let's shake on it: A random sample of 12-ounce milkshakes from 11 fast-food restaurants had the following number of calories.375 608 473 476 504 510 472700 642 591 580 Send data to ExcelAssume the population standard deviation is =σ85.Part 1 of 3(a) Explain why it is necessary to check whether the population is approximately normal before constructing a confidence interval.It is necessary to check whether the population is approximately normal because ▼the sample size is less than or equal to 30.Part 2 of 3(b) Following is a dotplot of these data. Is it reasonable to assume that the population is approximately normal?350400450500550600650700It ▼is reasonable to assume that the population is approximately normal.Part: 2 / 32 of 3 Parts CompletePart 3 of 3(c) If appropriate, construct an 80% confidence interval for the mean calorie count for all 12-ounce milkshakes sold at fast-food restaurants. Round the answers to at least two decimal places.An 80% confidence interval for the mean calorie count for all 12-ounce milkshakes sold at fast-food restaurants is <<μ.

Eat your cereal: Boxes of cereal are labeled as containing 14 ounces. Following are the weights, in ounces, of a sample of 14 boxes. It is reasonable to assume that the population is approximately normal.14.07 13.99 14.16 14.17 14.15 14.11 14.2413.99 14.14 14.13 14.20 14.21 14.06 14.05Send data to ExcelPart: 0 / 20 of 2 Parts CompletePart 1 of 2(a) Construct a 99.9% confidence interval for the mean weight. Round the answers to at least three decimal places.A 99.9% confidence interval for the mean weight is <<μ.

Use the following information for questions 17 and 18.You randomly select 16 restaurants and measure the temperature of the coffee sold at each. The sample mean temperature is 162 F with a standard deviation of 10 F. Assuming that the temperature of the coffee is approximately normally distributed. Find a 95% confidence interval for the mean temperature.Group of answer choices(172.6, 182.9)(171.5, 181.3)(144.7, 156.5)(168.9, 172.5)(156.7, 167.3)

a.Construct a 95%confidence interval estimate of the mean cost of a meal for restaurants that have a summated rating of 51. 19.857≤Y1X=×1≤26.923 (Type integers or decimals.Round to three decimal places as needed.Use ascending order.) b.Construct a 95%prediction interval of the cost of a meal for an individual restaurant that has a summated rating of 51. 4.498≤Yx=51≤42.283 (Type integers or decimals.Round to three decimal places as needed.Use ascending order.) c.Explain the differences in the results from (a)and(b).Choose the correct answer below. OA.Since there is more variation in estimating a mean value than in predicting an individual value,the confidence interval is narrower than the prediction interval,holding everything else fixed. B.Since there is more variation in estimating a mean value than in predicting an individual value,the confidence interval is wider than the prediction interval,holding everything else fixed. O C.Since there is more variation in predicting an individual value than in estimating a mean value,the prediction interval is wider than the confidence interval,holding everything else fixed. OD.Since there is more variation in predicting an individual value than in estimating a mean value,the prediction interval is narrower than the confidence interval,holding everything else fixed.