Select the correct answerA number consists of two digits and the digit in the ten’s place exceeds that in the unit’s place by 5. if 5 times the sum of the digits be added from the numbers, the digits of the number are reversed. Then the sum of digits of the number is?

Let's break down the problem step by step:

1. We know that the number is a two-digit number. Let's denote the tens digit as 'T' and the units digit as 'U'.

2. According to the problem, the tens digit exceeds the units digit by 5. So, we can write this as: T = U + 5.

3. The problem also states that if 5 times the sum of the digits is added to the number, the digits of the number are reversed. This can be written as: 10T + U + 5(T + U) = 10U + T.

4. Substituting T = U + 5 into the equation from step 3, we get: 10(U + 5) + U + 5(U + 5 + U) = 10U + U + 5.

5. Simplifying this equation, we get: 15U + 50 = 11U + 5.

6. Solving for U, we get: U = -9.

7. However, a digit cannot be negative, so there must be a mistake in the problem statement. The problem as stated does not have a valid solution.

Let's break down the problem step by step:

1. We know that the number is a two-digit number. Let's denote the tens digit as 'T' and the units digit as 'U'.

2. According to the problem, the tens digit exceeds the units digit by 5. So, we can write this as: T = U + 5.

3. The problem also states that if 5 times the sum of the digits is added to the number, the digits of the number are reversed. This can be written as: 10T + U + 5(T + U) = 10U + T.

4. Substituting T = U + 5 into the equation from step 3, we get: 10(U + 5) + U + 5(U + 5 + U) = 10U + U + 5.

5. Simplifying this equation, we get: 15U + 50 = 11U + 5.

6. Solving for U, we get: U = -9. However, a digit cannot be negative, so there must be a mistake in the problem statement.

7. Therefore, the sum of the digits of the number cannot be calculated based on the given information.