A two-digit number is such that the sum of the digits is 11. When the number with the same digits is reversed is subtracted from this number, the difference is 9.What is the number?23246514
Question
A two-digit number is such that the sum of the digits is 11. When the number with the same digits is reversed is subtracted from this number, the difference is 9.What is the number?23246514
Solution
Let's solve this step by step:
Step 1: Let's denote the tens digit as "x" and the units digit as "y". According to the problem, the sum of the digits is 11. So, we can write this as:
x + y = 11
Step 2: The problem also states that when the number with the same digits is reversed and subtracted from the original number, the difference is 9. We can write this as:
10x + y - (10y + x) = 9 9x - 9y = 9 x - y = 1
Step 3: Now we have a system of two equations, and we can solve it. From the second equation, we can express x as:
x = y + 1
Step 4: Substitute x in the first equation:
(y + 1) + y = 11 2y + 1 = 11 2y = 10 y = 5
Step 5: Substitute y = 5 in the equation x = y + 1:
x = 5 + 1 x = 6
So, the number is 65.
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