The answer is k1 + k2.

Here's why:

A DFA (Deterministic Finite Automaton) for a language A or B has a specific number of states, say k1 and k2 respectively.

When we take the union of two languages A and B, we are essentially combining the two languages into one. This means that the DFA for the union of A and B would need to accommodate for all the states in both A and B.

Therefore, the DFA for A union B would have at most k1 + k2 states. This is because it would need to include all the states from A's DFA and all the states from B's DFA.

Question

The answer is k1 + k2.

Here's why:

A DFA (Deterministic Finite Automaton) for a language A or B has a specific number of states, say k1 and k2 respectively.

When we take the union of two languages A and B, we are essentially combining the two languages into one. This means that the DFA for the union of A and B would need to accommodate for all the states in both A and B.

Therefore, the DFA for A union B would have at most k1 + k2 states. This is because it would need to include all the states from A's DFA and all the states from B's DFA.

Knowee AI · Accepted Answer

The answer is k1 + k2.

Here's why:

A DFA (Deterministic Finite Automaton) for a language A or B has a specific number of states, say k1 and k2 respectively.

When we take the union of two languages A and B, we are essentially combining the two languages into one. This means that the DFA for the union of A and B would need to accommodate for all the states in both A and B.

Therefore, the DFA for A union B would have at most k1 + k2 states. This is because it would need to include all the states from A's DFA and all the states from B's DFA.

For two languages A and B, let there be DFAs of k1 and k2 states respectively. Then, A union B has a DFA with at most __ states1 pointk1+k2k1k2k1^k2k1/k2

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