For an NFA with k states, there is a DFA with at most __ states.1 pointk^2k^3k2^k
Question
For an NFA with k states, there is a DFA with at most __ states.1 pointk^2k^3k2^k
Solution
For a Non-deterministic Finite Automaton (NFA) with k states, there is a Deterministic Finite Automaton (DFA) with at most 2^k states. This is because each state in the DFA represents a subset of the states in the NFA, and there are 2^k possible subsets of a set with k elements (including the empty set and the set itself). Therefore, in the worst case scenario, a DFA equivalent to an NFA could have up to 2^k states.
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