To solve this problem, we can use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

Step 1: Identify the initial molarity (M1) and volume (V1). In this case, M1 is 6.0 M and V1 is 2.0 mL.

Step 2: Identify the final volume (V2). In this case, V2 is 500.0 mL.

Step 3: Substitute the known values into the formula and solve for M2 (the final molarity).

6.0 M * 2.0 mL = M2 * 500.0 mL

Step 4: Solve for M2.

M2 = (6.0 M * 2.0 mL) / 500.0 mL = 0.024 M

So, the molarity of the dilute solution is 0.024 M.

Question

To solve this problem, we can use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

Step 1: Identify the initial molarity (M1) and volume (V1). In this case, M1 is 6.0 M and V1 is 2.0 mL.

Step 2: Identify the final volume (V2). In this case, V2 is 500.0 mL.

Step 3: Substitute the known values into the formula and solve for M2 (the final molarity).

6.0 M * 2.0 mL = M2 * 500.0 mL

Step 4: Solve for M2.

M2 = (6.0 M * 2.0 mL) / 500.0 mL = 0.024 M

So, the molarity of the dilute solution is 0.024 M.

Knowee AI · Accepted Answer

To solve this problem, we can use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

Step 1: Identify the initial molarity (M1) and volume (V1). In this case, M1 is 6.0 M and V1 is 2.0 mL.

Step 2: Identify the final volume (V2). In this case, V2 is 500.0 mL.

Step 3: Substitute the known values into the formula and solve for M2 (the final molarity).

6.0 M * 2.0 mL = M2 * 500.0 mL

Step 4: Solve for M2.

M2 = (6.0 M * 2.0 mL) / 500.0 mL = 0.024 M

So, the molarity of the dilute solution is 0.024 M.

f 2.0 mL of 6.0M HCl is used to make a 500.0-mL aqueous solution, what is the molarity of the dilute solution?

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