Calculate the molarity of a solution made by diluting 43.1mL of 0.614M HCl solution to a volume of 113.mL. Round your answer to 3 significant figures.Note: Reference the SI prefixes table for additional information.
Question
Calculate the molarity of a solution made by diluting 43.1mL of 0.614M HCl solution to a volume of 113.mL. Round your answer to 3 significant figures.Note: Reference the SI prefixes table for additional information.
Solution
To calculate the molarity of the solution after dilution, we can use the formula M1V1 = M2V2, where:
M1 = initial molarity V1 = initial volume M2 = final molarity (what we're solving for) V2 = final volume
Given in the problem, we have:
M1 = 0.614 M V1 = 43.1 mL V2 = 113 mL
We can plug these values into the formula and solve for M2:
(0.614 M)(43.1 mL) = M2(113 mL)
M2 = (0.614 M * 43.1 mL) / 113 mL
M2 = 0.234 M
So, the molarity of the solution after dilution is 0.234 M.
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