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What output will the following code produce?n = 10while n != 1:    print (n,end=' ')    if n % 2 == 0:        # n is even        n = n // 2    else:                # n is odd        n = n * 3 + 1Question 16Select one:a.10 5 16 8 4 2b.None an error will be displayedc.8 4 2d.9 28 14 7 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2

Question

What output will the following code produce?n = 10while n != 1:    print (n,end=' ')    if n % 2 == 0:        # n is even        n = n // 2    else:                # n is odd        n = n * 3 + 1Question 16Select one:a.10 5 16 8 4 2b.None an error will be displayedc.8 4 2d.9 28 14 7 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2

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Solution

The output of the given code will be:

10 5 16 8 4 2

So, the correct answer is option a.

Here's the step by step explanation:

  1. The initial value of n is 10.
  2. The while loop will continue as long as n is not equal to 1.
  3. In each iteration of the loop, it first prints the current value of n, followed by a space.
  4. Then it checks if n is even. If it is, it divides n by 2 using integer division (//).
  5. If n is not even (i.e., it's odd), it multiplies n by 3 and adds 1.
  6. This process repeats until n becomes 1.
  7. So, the sequence of numbers printed is: 10 (initial value), 5 (10/2), 16 (5*3+1), 8 (16/2), 4 (8/2), 2 (4/2). The loop then stops because n is now 1.

This problem has been solved

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