This problem can be solved using the equations of motion.

Step 1: Understand the problem
The object is dropped from a tower, so the initial velocity (u) is 0. The acceleration (a) is due to gravity, so it's 9.8 m/s². We don't know the total time of flight (t) or the total distance (h), but we know that the distance covered in the last second of flight is seven times the distance covered in the first second.

Step 2: Apply the equations of motion
The distance covered in the first second (h1) can be found using the equation h = ut + 0.5at². Since u = 0 and t = 1, h1 = 0.5 * 9.8 * 1² = 4.9 m.

The distance covered in the last second (h2) is seven times this, so h2 = 7 * 4.9 = 34.3 m.

Step 3: Find the total distance
The total distance (h) is the sum of h1 and h2, so h = 4.9 + 34.3 = 39.2 m.

Step 4: Find the total time of flight
We can find the total time of flight (t) using the equation h = ut + 0.5at². Since u = 0, h = 0.5at². Solving for t gives t = sqrt(2h/a) = sqrt(2*39.2/9.8) = sqrt(8) = 2.83 seconds.

So, the time of flight is approximately 2.83 seconds.

Question

This problem can be solved using the equations of motion.

Step 1: Understand the problem
The object is dropped from a tower, so the initial velocity (u) is 0. The acceleration (a) is due to gravity, so it's 9.8 m/s². We don't know the total time of flight (t) or the total distance (h), but we know that the distance covered in the last second of flight is seven times the distance covered in the first second.

Step 2: Apply the equations of motion
The distance covered in the first second (h1) can be found using the equation h = ut + 0.5at². Since u = 0 and t = 1, h1 = 0.5 * 9.8 * 1² = 4.9 m.

The distance covered in the last second (h2) is seven times this, so h2 = 7 * 4.9 = 34.3 m.

Step 3: Find the total distance
The total distance (h) is the sum of h1 and h2, so h = 4.9 + 34.3 = 39.2 m.

Step 4: Find the total time of flight
We can find the total time of flight (t) using the equation h = ut + 0.5at². Since u = 0, h = 0.5at². Solving for t gives t = sqrt(2h/a) = sqrt(2*39.2/9.8) = sqrt(8) = 2.83 seconds.

So, the time of flight is approximately 2.83 seconds.

Knowee AI · Accepted Answer

This problem can be solved using the equations of motion.

Step 1: Understand the problem
The object is dropped from a tower, so the initial velocity (u) is 0. The acceleration (a) is due to gravity, so it's 9.8 m/s². We don't know the total time of flight (t) or the total distance (h), but we know that the distance covered in the last second of flight is seven times the distance covered in the first second.

Step 2: Apply the equations of motion
The distance covered in the first second (h1) can be found using the equation h = ut + 0.5at². Since u = 0 and t = 1, h1 = 0.5 * 9.8 * 1² = 4.9 m.

The distance covered in the last second (h2) is seven times this, so h2 = 7 * 4.9 = 34.3 m.

Step 3: Find the total distance
The total distance (h) is the sum of h1 and h2, so h = 4.9 + 34.3 = 39.2 m.

Step 4: Find the total time of flight
We can find the total time of flight (t) using the equation h = ut + 0.5at². Since u = 0, h = 0.5at². Solving for t gives t = sqrt(2h/a) = sqrt(2*39.2/9.8) = sqrt(8) = 2.83 seconds.

So, the time of flight is approximately 2.83 seconds.

An object is dropped from the top of a tower. the distance it covers in the last second is seven time the distance it covered in the first second . find the time of flight

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