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A body falling from rest was observed to fall through 78.4 m in 2 seconds. Find how long had it been falling before it was observed? (g = 9.8 m/s2)A 5 seconds B 1 second C 3 seconds D 10 seconds

Question

A body falling from rest was observed to fall through 78.4 m in 2 seconds. Find how long had it been falling before it was observed? (g = 9.8 m/s2)A 5 seconds B 1 second C 3 seconds D 10 seconds

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Solution

The problem involves the physics concept of free fall. The formula for the distance covered in free fall is given by:

d = 0.5 * g * t^2

where: d = distance (in meters) g = acceleration due to gravity (in m/s^2) t = time (in seconds)

We know that the body fell 78.4 m in 2 seconds. So, we can substitute these values into the formula to find the total time the body had been falling:

78.4 = 0.5 * 9.8 * t^2

Solving for t gives:

t^2 = 78.4 / (0.5 * 9.8) t^2 = 16 t = sqrt(16) t = 4 seconds

This means the body had been falling for 4 seconds in total. However, we know that the body was observed to fall for 2 seconds. Therefore, the body had been falling for 4 - 2 = 2 seconds before it was observed.

So, none of the options A, B, C, D are correct. The correct answer should be 2 seconds.

This problem has been solved

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