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An object is thrown downward with an initial velocity of 3 feet per second. The relationship between the distance 𝑠 it travels and time 𝑡 is given by 𝑠=3⁢𝑡+16⁢𝑡2. How long does it take the object to fall 70 feet?It takes seconds for the object to fall 70 feet.

Question

An object is thrown downward with an initial velocity of 3 feet per second. The relationship between the distance 𝑠 it travels and time 𝑡 is given by 𝑠=3⁢𝑡+16⁢𝑡2. How long does it take the object to fall 70 feet?It takes seconds for the object to fall 70 feet.

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Solution

To find out how long it takes for the object to fall 70 feet, we need to set the equation for the distance s equal to 70 and solve for time t.

The equation given is s = 3t + 16t^2.

We set this equal to 70:

70 = 3t + 16t^2

Rearrange the equation to look like a standard quadratic equation (ax^2 + bx + c = 0):

16t^2 + 3t - 70 = 0

Now we can solve this quadratic equation for t using the quadratic formula, t = [-b ± sqrt(b^2 - 4ac)] / (2a):

t = [-(3) ± sqrt((3)^2 - 416(-70))] / (2*16)

t = [-3 ± sqrt(9 + 4480)] / 32

t = [-3 ± sqrt(4489)] / 32

t = [-3 ± 67] / 32

This gives us two possible solutions: t = 2 or t = -2.2.

However, time cannot be negative, so we discard the negative solution.

Therefore, it takes 2 seconds for the object to fall 70 feet.

This problem has been solved

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