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A body is thrown up with a velocity 40m𝑠-1. At same time another body is dropped from a height 40 m. Their relative acceleration after 1.3 seconds is

Question

A body is thrown up with a velocity 40m𝑠-1. At same time another body is dropped from a height 40 m. Their relative acceleration after 1.3 seconds is

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Solution

The relative acceleration between two bodies is the difference in their individual accelerations.

  1. The first body is thrown upwards with an initial velocity. However, regardless of its initial velocity, a body moving under the influence of gravity alone (in the absence of other forces like air resistance) always has a constant acceleration equal to the acceleration due to gravity. This is directed downwards and has a magnitude of approximately 9.8 m/s².

  2. The second body is dropped from a height. This means it is also moving under the influence of gravity alone, so it also has a constant acceleration of 9.8 m/s² downwards.

Therefore, the acceleration of both bodies is the same (9.8 m/s² downwards), so their relative acceleration is 0.

In other words, each body 'sees' the other as moving with a constant velocity, not accelerating.

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