21484Po + 242He + 20-1e → ______ 22286Rn22286At22288Ra22286Fr
Question
21484Po + 242He + 20-1e → ______ 22286Rn22286At22288Ra22286Fr
Solution
The equation you've provided seems to be a nuclear reaction involving Polonium (Po), Helium (He), an electron (e), and resulting in some unknown product. However, the equation is not balanced correctly, which makes it difficult to determine the final product.
In a balanced nuclear equation, the sum of the atomic numbers (the superscripts) and the sum of the mass numbers (the subscripts) should be the same on both sides of the equation.
Let's try to balance the equation:
21484Po + 242He + 20-1e → ______
The sum of the atomic numbers on the left side is 84 (from Po) + 2 (from He) - 1 (from e) = 85.
The sum of the mass numbers on the left side is 214 (from Po) + 4 (from He) = 218.
So, we're looking for a nucleus with atomic number 85 and mass number 218. This corresponds to Astatine (At), so the balanced equation should be:
21484Po + 242He + 20-1e → 21885At
Please note that this is a theoretical reaction, as the actual nuclear reactions can be more complex and may involve other particles or energy in the form of gamma radiation.
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