This is a nuclear reaction, specifically alpha decay. In alpha decay, an alpha particle (which is a helium nucleus, 42He) is emitted from the nucleus of the parent atom. The atomic number decreases by 2 and the mass number decreases by 4.

The parent atom here is 23994Pu (Plutonium-239).

The atomic number (94) minus 2 gives 92, and the mass number (239) minus 4 gives 235.

So, the product of the decay is 23592U, which is Uranium-235.

Therefore, the correct answer is D. 23592U.

Question

This is a nuclear reaction, specifically alpha decay. In alpha decay, an alpha particle (which is a helium nucleus, 42He) is emitted from the nucleus of the parent atom. The atomic number decreases by 2 and the mass number decreases by 4.

The parent atom here is 23994Pu (Plutonium-239).

The atomic number (94) minus 2 gives 92, and the mass number (239) minus 4 gives 235.

So, the product of the decay is 23592U, which is Uranium-235.

Therefore, the correct answer is D. 23592U.

Knowee AI · Accepted Answer

This is a nuclear reaction, specifically alpha decay. In alpha decay, an alpha particle (which is a helium nucleus, 42He) is emitted from the nucleus of the parent atom. The atomic number decreases by 2 and the mass number decreases by 4.

The parent atom here is 23994Pu (Plutonium-239).

The atomic number (94) minus 2 gives 92, and the mass number (239) minus 4 gives 235.

So, the product of the decay is 23592U, which is Uranium-235.

Therefore, the correct answer is D. 23592U.

23994Pu → ___ + 42He A. 23693UB. 23692UC. 23593UD. 23592U

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