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24195Am + 42He →  210n +  _____ A. 24396CmB. 24498CfC. 24397BkD. 24399Es

Question

24195Am + 42He →  210n +  _____ A. 24396CmB. 24498CfC. 24397BkD. 24399Es

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Solution

This is a nuclear reaction, specifically an alpha decay, where an alpha particle (4/2 He) is emitted. To find the missing product, we need to balance the atomic and mass numbers.

The atomic number (number of protons) before the reaction is 95 (from Am) + 2 (from He) = 97. The atomic number after the reaction is 0 (from n), so the atomic number of the missing product must be 97 to balance the equation.

The mass number (number of protons + neutrons) before the reaction is 241 (from Am) + 4 (from He) = 245. The mass number after the reaction is 210 (from n), so the mass number of the missing product must be 245 - 210 = 35 to balance the equation.

So, we are looking for an element with atomic number 97 and mass number 35. However, none of the options A, B, C, D match these numbers. There seems to be a mistake in the question. The mass number of the missing product should be 245 - 210 = 35, but none of the options have a mass number of 35.

This problem has been solved

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