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What is the output of the following code?1234567891011#include <stdio.h>int main() { char c = 'K'; char* ptr = &c; (*ptr)++; printf("%c ", *ptr); (*ptr)--; printf("%c", *ptr); return 0;}

Question

What is the output of the following code?1234567891011#include <stdio.h>int main() { char c = 'K'; char* ptr = &c; (*ptr)++; printf("%c ", *ptr); (*ptr)--; printf("%c", *ptr); return 0;}

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Solution

The output of the code will be "L K".

Here's the step by step explanation:

  1. The character variable 'c' is initialized with the value 'K'.
  2. A pointer 'ptr' is created that points to the address of 'c'.
  3. The value at the address that 'ptr' points to (which is 'c') is incremented by 1. Since 'c' was 'K', after incrementing it becomes 'L'.
  4. The new value of 'c' ('L') is printed.
  5. The value at the address that 'ptr' points to is decremented by 1, so it becomes 'K' again.
  6. The value of 'c' ('K') is printed again.

So, the output is "L K".

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