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What is the output for the following code?123456789#include <stdio.h>int main(){ char ch = '1'; for (ch = '5'; ch <= '8'; ch++) putchar(ch); return (0);}

Question

What is the output for the following code?123456789#include <stdio.h>int main(){ char ch = '1'; for (ch = '5'; ch <= '8'; ch++) putchar(ch); return (0);}

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Solution

The output for the given C code will be "5678".

Here's the step by step explanation:

  1. The character variable ch is initially assigned the value '1'.
  2. Then, in the for loop, ch is reassigned the value '5'.
  3. The loop will continue to execute as long as the value of ch is less than or equal to '8'.
  4. In each iteration of the loop, the putchar(ch) function is called, which prints the current value of ch to the standard output.
  5. The value of ch is then incremented by 1.
  6. This process repeats until ch is '8', at which point the loop terminates.
  7. Therefore, the characters '5', '6', '7', and '8' are printed to the standard output, resulting in the output "5678".

This problem has been solved

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