Which solution contains the biggest amount, in mol, of chloride ions?A. 20 cm3 of 0.50 moldm−3NH4ClB. 60 cm3 of 0.20 moldm−3MgCl2C. 70 cm3 of 0.30 moldm−3NaClD. 100 cm3 of
Question
Which solution contains the biggest amount, in mol, of chloride ions?A. 20 cm3 of 0.50 moldm−3NH4ClB. 60 cm3 of 0.20 moldm−3MgCl2C. 70 cm3 of 0.30 moldm−3NaClD. 100 cm3 of
Solution
To find out which solution contains the biggest amount of chloride ions, we need to calculate the number of moles in each solution.
The number of moles (n) can be calculated using the formula: n = concentration (c) x volume (V). The volume should be in dm^3, so we need to convert cm^3 to dm^3 by dividing by 1000.
A. n = 0.50 mol/dm^3 x (20 cm^3 / 1000) = 0.01 mol of NH4Cl. Each NH4Cl has one Cl-, so there are 0.01 mol of Cl- ions.
B. n = 0.20 mol/dm^3 x (60 cm^3 / 1000) = 0.012 mol of MgCl2. Each MgCl2 has two Cl-, so there are 0.012 mol x 2 = 0.024 mol of Cl- ions.
C. n = 0.30 mol/dm^3 x (70 cm^3 / 1000) = 0.021 mol of NaCl. Each NaCl has one Cl-, so there are 0.021 mol of Cl- ions.
D. n = 0.10 mol/dm^3 x (100 cm^3 / 1000) = 0.01 mol of NaCl. Each NaCl has one Cl-, so there are 0.01 mol of Cl- ions.
So, the solution B contains the biggest amount of chloride ions.
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