A car moving initially at 20m/s, reduces its speed uniformlyand comes to rest through a displacement of 50m. Find the accelaration of the car.a.-4m/sb.44m/sc.3.2m/sd.-8m/s
Question
A car moving initially at 20m/s, reduces its speed uniformlyand comes to rest through a displacement of 50m. Find the accelaration of the car.a.-4m/sb.44m/sc.3.2m/sd.-8m/s
Solution
The acceleration of the car can be found using the equation of motion:
v^2 = u^2 + 2as
where: v = final velocity u = initial velocity a = acceleration s = displacement
Rearranging the equation to solve for a, we get:
a = (v^2 - u^2) / 2s
Plugging in the given values:
a = ((0 m/s)^2 - (20 m/s)^2) / (2*50 m) a = (-400 m²/s²) / 100 m a = -4 m/s²
Therefore, the acceleration of the car is -4 m/s². The negative sign indicates that the car is decelerating, or slowing down.
The correct answer is:
a. -4m/s²
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