If log102 = p and log103 = q, the value of log12536 is equal to which of the following?

The given question is a logarithmic problem. Here's how you can solve it:

First, we need to express the number 12536 in terms of 2 and 3. The prime factorization of 12536 is 2^4 * 3^4 * 7^2.

So, log10(12536) can be written as log10(2^4 * 3^4 * 7^2).

Using the properties of logarithms, this can be further simplified to 4log10(2) + 4log10(3) + 2*log10(7).

We know from the problem that log10(2) = p and log10(3) = q. Substituting these values, we get 4p + 4q + 2*log10(7).

So, the value of log10(12536) is equal to 4p + 4q + 2*log10(7).

The given question is a logarithmic problem. Here's how you can solve it:

First, we need to express the number 12536 in terms of 2 and 3. The prime factorization of 12536 is 2^4 * 3^4 * 7^2.

Then, we can use the properties of logarithms to express log12536 in terms of p and q.

log12536 = log(2^4 * 3^4 * 7^2) = 4log2 + 4log3 + 2log7 = 4p + 4q + 2log7

So, the value of log12536 is equal to 4p + 4q + 2log7.